Question

22 400 mL of oxygen gas contains 6.022 1023 oxygen molecules at 0°C and standard atmospheric pressure. a. How many oxygen molecules are in 0.100 mL of gas? b. How many oxygen molecules are in 1.00 L of gas? c. What is the average space in milliters occupied by one oxygen molecule?

Answer 1

(a) The number of oxygen molecules present in 0.100 mL of gas is,
`2.688* 10^(18)`

(b) The number of oxygen molecules present in 1.0 L of gas is,
`2.688* 10^(22)`

(c) The volume of oxygen gas is,
`3.719* 10^(-20)mL`

Explanation :

(a) To calculate the number of oxygen molecules present in 0.100 mL of gas.

As, 22400 mL of oxygen gas contains
`6.022* 10^(23)` number of oxygen molecules

So, 0.100 mL of oxygen gas contains
`(0.100)/(22400)* 6.022* 10^(23)=2.688* 10^(18)` number of oxygen molecules

(b) To calculate the number of oxygen molecules present in 1.00 L or 1000 mL of gas.

As, 22400 mL of oxygen gas contains
`6.022* 10^(23)` number of oxygen molecules

So, 1000 mL of oxygen gas contains
`(1000)/(22400)* 6.022* 10^(23)=2.688* 10^(22)` number of oxygen molecules

(c) To calculate the volume of oxygen gas for one molecule of oxygen.

As,
`6.022* 10^(23)` number of oxygen molecules present in 22400 mL of oxygen gas

So, 1 oxygen molecules present in
`(1)/(6.022* 10^(23))* 22400mL=3.719* 10^(-20)mL` of oxygen gas