Question

asked Nov 22, 2020 53.2k views

2 Answers

Train · Answer 1 · 2020-11-23T08:00:11+0000

Answer:

The distance of AB rounded to the nearest tenth is:

2.8 units

We know that the distance between the two points :

$(x_1,y_1)\ and\ (x_2,y_2)$ is calculated using the distance formula as:

d=√((x_2-x_1)^2+(y_2-y_1)^2)

Here point A lie at (-3,1) and point B lie at (-1,-1)

Hence, the distance between A and B is given by:

$d=√((-3-(-1))^2+(1-(-1))^2)\\\\d=√((-2)^2+2^2)\\\\d=√(4+4)\\\\d=√(8)\\\\d=2.8284$

which to the nearest tenth is:

$d=2.8\ units$

Amia · Answer 2 · 2020-11-27T07:23:39+0000

Answer:

Distance is 2.83 units

Explanation:

We are given a straight line on graph and asked to find its length using Distance Formula. The Distance formula is given as under

D=√((y_2-y_1)^2+(x_2-x_1)^2)

Where

(x_1,y_1) = (-3,1))

(x_2,y_2) = (-1,-1)

Putting these values in Distance Formula we get

D=√((1-(-1))^2+(-3-(-1))^2)

D=√((2)^2+(-2)^2)

D=√(4+4)

D=√(8)

D=2√(2)

$D=2 \time 1.414$

D=2.828