Y = (2x-12)/3
We have to find where the x intercept is.
(2x-12)/3 = 0
2x=12
X = 6
When x = 0, y = -4
We have to take the integral from 0->6
pi * integral(0->6) (((2x-12)/3)^2)dx
pi * integral(0->6) ((4x^2 - 48x + 144)/9)dx
4pi/9 * integral(0->6)(x^2 - 12x + 36)dx
4pi/9 * (x^3/3 - 6x^2 + 36x) [0->6]
4pi/9 (6^3/3 - 6(36) + 36(6))
4pi/9 (72)
4pi(8)
32pi = 100.53 units ^3, or B