Question

Please help me !!!!!!!

1.Calculate the end velocity of a rocket that traveled 16km in 2 seconds.

distance

time



2.Calculate the rockets acceleration m with a start velocity of 0m/s and the end velocity from #1 for 10 seconds.



(final velocity- start velocity)

time



* Be sure to include units!

Answer 1

Hi, the answer to number one was 8 so...

8/10 = 0.8

You're from k12 right? :)

Answer 2

Step-by-step explanation:

1. Distance covered by the rocket,
`d=16\ km=16* 10^3\ m`

Time taken, t = 2 s

The velocity of rocket is given by:

`v=(d)/(t)`

`v=(16* 10^3\ m)/(2\ s)`

v = 8000 m/s

So, the velocity of a rocket is 8000 m/s.

2. Starting velocity of the rocket, u = 0

Final velocity, v = 8000 m/s

Time taken, t = 10 s

Change in speed, (v-u) = 8000 m/s

Acceleration of rocket is given by :

`a=(v-u)/(t)`

`a=(8000\ m/s)/(10\ s)`

`a=800\ m/s^2`

So, the acceleration of the rocket is
`800\ m/s^2`. Hence, this is the required solution.