Step-by-step explanation:
Methane (CH₄)
Valence electrons of carbon = 4
Valence electrons of hydrogen = 1
The total number of the valence electrons = 4 + 4(1) = 8
The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,
The Lewis structure is:
H
:
H : C : H
:
H
Ethylene (C₂H₄)
Valence electrons of carbon = 4
Valence electrons of hydrogen = 1
The total number of the valence electrons = 2(4) + 4(1) = 12
The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,
H H
: :
C : : C
: :
H H
Ethane (C₂H₆)
Valence electrons of carbon = 4
Valence electrons of hydrogen = 1
The total number of the valence electrons = 2(4) + 6(1) = 14
The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,
H H
: :
H : C : C : H
: :
H H
Propyne (H₃CCCH)
Valence electrons of carbon = 4
Valence electrons of hydrogen = 1
The total number of the valence electrons = 3(4) + 4(1) = 16
The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,
H
:
H : C : C : : : C : H
:
H
Diacetylene (HCCCCH)
Valence electrons of carbon = 4
Valence electrons of hydrogen = 1
The total number of the valence electrons = 4(4) + 2(1) = 18
The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,
H : C : : : C : C : : : C : H