Question

What are the roots of the equation -3x + 19 = -x^2+1​

Answer 1

• (3 ± 3√7i)/2

Explanation:

• -3x + 19 = -x^2+1​
• x^2 - 3x + 19 - 1 = 0
• x^2 - 3x + 18 = 0
• x = (3 ± √9 - 72)/2
• x = (3 ± √-63)/2
• x = (3 ± 3√7i)/2

It has no real solutions and two complex roots