Question

-5/3 is a root of f(x) = (3x + 5) (x2 - 6x + 9)2 = 0 True False

Answer 1

false...................

Answer 2

For this case we have the following function:

`f (x) = (3x + 5) (x ^ 2-6x + 9) ^ 2`

To find the roots we must equal the function to 0, that is:

`(3x + 5) (x ^ 2-6x + 9) ^ 2 = 0`

So:

`3x + 5 = 0`

Subtracting 5 from both sides:

`3x = -5`

Dividing between 3 on both sides:

`x = - \frac {5} {3}`

Thus, one of the roots is
`x = - \frac {5} {3}`

Answer:

True