Question

The relationship between the molar concentration of silver ion in a saturated solution of silver phosphate and the solubility product constant for silver phosphate is ________.

Answer 1

Answer: The solubility product of
`Ag_3PO_4` is
`27s^4`

Step-by-step explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as
`K_(sp)`

`Ag_3PO_4\leftrightharpoons 3Ag^++PO_4^(3-)`

We are given:

Solubility of
`Ag_3PO_4` = S mol/L

By stoichiometry of the reaction:

1 mole of
`Ag_3PO_4` gives 3 moles of
`Ag^(+)` and 1 mole of
`PO_4^(3-)`.

When the solubility of
`Ag_3PO_4` is S moles/liter, then the solubility of
`Ag^(+)` will be 3S moles\liter and solubility of
`PO_4^(3-)` will be S moles/liter.

Expression for the equilibrium constant of
`Ag_2CrO_4` will be:

`K_(sp)=[Ag^+]^3[PO_4^(3-)]`

`K_(sp)=[3s]^3[s]=27s^4`

The solubility product of
`Ag_3PO_4` is
`27s^4`