Question

You are throwing a stone straight-up in the absence of air friction. The stone is caught at the same height from which it was thrown. Determine the validity of the following statements

the acceleration is constant
the acceleration is "up" while it is still moving up, and "down" when it is on the way down.
the acceleration is maximum at the top point of the motion

Answer 1

The acceleration of the stone when thrown straight-up and caught at the same height is constant. It is 'up' while moving up and 'down' when on the way down. The acceleration is maximum at the top point of the motion.

Step-by-step explanation:

The acceleration of the stone when it is thrown straight-up and caught at the same height is constant. The acceleration is in the opposite direction of the motion, so it is 'up' while the stone is still moving up and 'down' when it is on the way down. At the top point of the motion, the acceleration is maximum because the stone momentarily comes to a stop and changes direction. This is due to the constant acceleration of gravity pulling the stone downwards.

Answer 2

the acceleration is constant

Step-by-step explanation:

When stone is moving in the air then it has force of gravity on it

Since there is no other force like air friction is to be neglected

so we know that

`F_(net) = mg`

so we will have

`a = (F_(net))/(m)`

`a = (mg)/(m)`

`a = g`

so the acceleration of the stone is always constant and directed vertically downwards with constant magnitude