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How many solutions are possible for a triangle with B=44,a23 and b=12

1 Answer

1 vote

Answer:

There are no possible solutions with the given dimensions.

Explanation:

There are no possible solutions with the given dimensions:

Use the law of sine to solve Angle A.

b/sinB = a/sinA

B=44

a= 23

b=12

12/sin44 = 23/sinA

By cross multiplication we get:

12*sinA = 23*sin44

sinA = 23*sin44/12

sinA = 23* 0.6947/12

sinA = 15.9781 / 12

sinA= 1.331

Since sinx is only defined for values between -1 and 1 it is impossible to form a triangle....

User ShaneG
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