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Algebra II
15 points

Algebra II 15 points-example-1
Algebra II 15 points-example-1
Algebra II 15 points-example-2

1 Answer

4 votes

Answer:

B. The axis of symmetry is x=1.

F. The vertex is (1, 7).

G. The y-intercept is (0, 10).

Explanation:

A graph of the function is helpful sorting this out.

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For quadratic ax² +bx +c, the axis of symmetry is x=-b/(2a). Here, that is ...

x = -(-6)/(2·3)

x = 1 . . . . axis of symmetry

This is also the x-coordinate of the vertex. The y-coordinate of the vertex can be found by evaluating the expression for this value of x:

3·1² -6·1 +10 = 7

so the vertex is (1, 7).

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The y-intercept is the constant, the value of the function when x=0. Here, that is 10, so the coordinates of the y-intercept are (0, 10).

Algebra II 15 points-example-1
User Jack Koppa
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