Question

1.Calculate the end velocity of a rocket that traveled 16km in 2 seconds. distance time 2.Calculate the rockets acceleration m with a start velocity of 0m/s and the end velocity from #1 for 10 seconds. (final velocity- start velocity) time * Be sure to include units!

Answer 1

Step-by-step explanation:

1. The rocket covered a distance,
`d=16\ km=16000\ m`

Time taken, t = 2 s

The velocity of rocket is given by total distance over total time. It is given by :

`v=(d)/(t)`

`v=(16000\ m)/(2\ s)`

v = 8000 m/s

2. Initial velocity of the rocket, u = 0

Final velocity of the rocket in part 1, v = 8000 m/s

Time taken, t = 10 s

Acceleration of rocket is given change in speed divided by total time. It is given by :

`a=(v-u)/(t)`

`a=(8000\ m/s)/(10\ s)`

`a=800\ m/s^2`

So, the acceleration of the rocket is
`800\ m/s^2`. Hence, this is the required solution.

Answer 2

1. 8 km/s 2. 0,8 km/s^2

Step-by-step explanation:

Velocity:

`v=(16 [km])/(2[s]) =8(km)/(s)`

Acceleration:

`a=(8(km)/(s)-0(km)/(s) )/(10[s])=0,8(km)/(s^2)`