Question

What is an equation of the line that passes through the point

(−8,−1) and is parallel to the line x−4y=4?

Answer 1

Answer:
`y=(1)/(4)x+1`

Explanation:

`x-4y=4\\\\4y-x=-4\\\\4y=x-4\\\\y=(1)/(4)x-1`

The slope of the given line is 1/4, so since parallel lines have the same slope, point-slope form gives us that the equation is

`y+1=(1)/(4)(x+8)\\\\`

Rearranging into slope-intercept form,

`y+1=(1)/(4)x+2\\ \\ y=(1)/(4)x+1`