2 Answers

Miklos Krivan · Answer 1 · 2020-01-25T09:35:15+0000

Answer:

His overall grade is 81.9%

Step-by-step explanation:

The easiest way to solve this question is by using simple cross multiplication.

1- His overall percentage in exams:

We are given that exams are worth 50% of the grade and that he scored an average of 82.2%

Assume that his overall percentage in exams is e

We can setup the ratio and solve for e as follows:

$(82.2)/(100)=(e)/(50) \\ \\e=(50*82.2)/(100)=41.1$ %

2- His overall grade in quizzes:

We are given that quizzes are worth 30% of the grade and that he scored 74.4%

Assume that his overall percentage in quizzes is q

We can setup the ratio and solve for q as follows:

$(74.4)/(100)=(q)/(30) \\ \\q=(30*74.4)/(100)=22.32$ %

3- His overall grade in homework:

We are given that homework is worth 15% of the grade and that he scored an average of 90%

Assume that his overall percentage in exams is h

We can setup the ratio and solve for h as follows:

$(90)/(100)=(h)/(15) \\ \\h=(15*90)/(100)=13.5$ %

4- His overall grade in class participation:

We are given that class participation is worth 5% of the grade and that he scored a 100% in it

Assume that his overall percentage in exams is p

Since he scored 100%, then he scored the complete worth which is 5%

p = 5%

5- His overall grade in the course:

The student's overall grade in the course is the summation of the above calculated percentages

This means that:

Overall grade = e + q + h + p

Overall grade = 41.1 + 22.32 + 13.5 + 5

Overall grade = 81.92% which is 81.9% approximated to one decimal place

Hope this helps :)

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