Question

Let f(x) = 1 / x and g(x) = x ^ 2 - 2. What is (f g)(-3) )?

Answer 1

`f(g(-3))=1/7`

Explanation:

we have

`f(x)=(1)/(x)`

`g(x)=x^(2) -2`

we know that

`(fg)(x)=f(g(x))=(1)/(x^(2) -2)`

For x=-3

substitute

`f(g(-3))=(1)/((-3)^(2) -2)=1/7`

therefore

`f(g(-3))=1/7`