Question

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In the figure, m
Bm4C and 2D is a right angle.
cos B=
sin A
>
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sin D
O

Answer 1

sin A gotta be the answer

Step-by-step explanation:

Answer 2

• sin (A)

Step-by-step explanation:

In the given figure the "hidden" vertex of the larger triangle is A.

Since, angle D is a right angle, both triangles BDC and CDE are right triangles (and they are also similar).

Since angle B and angle C have the same measure and angle D measures 90° (right angle), angle A and angle C are complementary, i.e.

• ∠ C + ∠ A = 90°

For complementary angles, the sine of one acute angle equals the cosine of the other acute angle.

So, the sine of angle C is equal to the cosine of angle B, i.e. cos (B) = sin (A).