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What is the equation of a line perpendicular to y=¼x-3 that passes through point (-2,4)
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Aug 7, 2020
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What is the equation of a line perpendicular to y=¼x-3 that passes through point (-2,4)
Mathematics
high-school
Nicq
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Answer:
y = -4x - 4
Explanation:
Carrdelling
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Aug 8, 2020
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Carrdelling
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In order for a line to be perpendicular, its slope must be the negative reciprocal of the other line. We’re solving for the b part of y = mx + b
The new line = -4x + b
4 = -4(-2) + b
4 = 8 + b
b = -4
The equation of the line is y = -4x - 4
Fiz
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Aug 11, 2020
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