Question

If the solubility product of silver chromate is 2 x 10-12 at 25°C, what is the solubility in mole/liter of silver chromate?

Answer 1

Solubility of silver chromate =
`0.7937*10^(-4)\;mol/L`

Step-by-step explanation:

Given,

`Ag_2CrO_4\leftrightharpoons2Ag^(+)\;+\;CrO4^(2-)`

Solubility product (Ksp) = 2 x 10-12

at equilibrium,
`[Ag^(+)]` = 2x,
`[CrO4^(2-)]` = x

`Ksp=[Ag^(+)]^(2)[CrO_4^(2-)]\\2*10^(-12)=(2x)^(2)(x)\\2*10^(-12)=(4x)^(3)\\(x)^(3) = (2*10^(-12))/(4)\\\\\sqrt[3]{5*10^(-13)}`

`x=\sqrt[3]{0.5*10^(-12)} =0.7937*10^(-4)\;mol/L`