Question

How do I factor completely 8y^2+4y-6ay-3a

Answer 1

(2y+1)(4y+3a)

Explanation:

The given expresion is:

`8 {y}^(2) + 4y - 6ay - 3a`

We need to factor by grouping.

`4y(2y + 1) - 3a(2y + 1)`

`(2y + 1)(4y - 3a)`

Now we cannot factorize further.

Therefore the complete factorization of the given expresion is (2y+1)(4y-3a)