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A restaurant’s dining room measures 30 ft by 40 ft. If the fire code requires one square meter per guest, what is the seating capacity?

User Jason John
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2 Answers

1 vote
The restaurant is 30*40= 1200 square feet

1 square meter is 10.76 sq feet

1200/10.76 ~=111.5

Assuming people are integers, the restaurant has a max seating capacity of 111
User Piegames
by
8.3k points
4 votes

Answer:

111 guest

Explanation:

It is given that a restaurant’s dining room measures 30 ft by 40 ft.

Area of a rectangle is


Area=length* width

Area of the restaurant’s dining room floor is


Area=30* 40


Area=1200

The area of the floor is 1200 square feet.

It is given that the fire code requires one square meter per guest.

We know that

1 square ft = 0.092903 square meter

1200 square ft = 1200 × 0.092903 square meter

1200 square ft = 111.4836 square meter

The number of guests can not be a fraction values. So approx the value to the preceding integer.


111.4836\approx 111

Therefore, the seating capacity of restaurant is 111.

User Omalave
by
9.1k points
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