Answer:
Tina would save the same amount using either option after 20 months.
With either option, Tina would save $700.
Explanation:
This problem can be modeled by a first order equation:
Where Tina's saved money after n months is:
S(n) = S(0) + rn, where S(0) is the money put away initially and r is how much she saves every month.
The first option is to put $500 away initially and save $10 every month, so:

The second option is to put $100 away initially and save $30 every month, so:

After how many months would Tina save the same amount using either option?
It will happen at the month n in which
, so:

500 + 10n = 100 + 30n
500 - 100 = 30 - 10n
400 = 20n
20n = 400

n = 20.
Tina would save the same amount using either option after 20 months.
How much would she save with either option?
We can choose
or
, since they are equal

With either option, Tina would save $700.