Answer:
a. He can cut 5 strips of length 7/10 m
b. He has 6/7 m of wire left over
Explanation:
* Lets explain how to solve the problem
- The length of the wire is 4.1 meters
- We need to cut strips from this wire of 7/10 meter long
- To do that lets divide the length of the wire by the length of
each strip
∵ The length of the wire = 4.1 meters
∵ The length of each strip = 7/10 meter
∴ The number of strips = 4.1 ÷ 7/10
- Lets change the decimal number 4.1 to a fraction
∵ 4.1 = 41/10
∴ The number of strips = 41/10 ÷ 7/10
- Multiply both terms by 10 to cancel the denominators
∴ The number of strips = 41 ÷ 7
∵ 41 ÷ 7 = 5 6/7
∴ The number of strips = 5 6/7
- That means the quotient is 5 and the reminder is 6
a.
∵ The quotient is the number of the strips
∴ The number of strips is 5
* He can cut 5 strips of length 7/10 m
b.
∵ The (remainder/divisor) is the left over
∴ The left over is 6/7
* He has 6/7 m of wire left over