Question

A solution of copper sulfate is treated with zincmetal. How many grams of copper are produced if 2.9 g of zinc are consumed?

Answer 1

2.8212 g

Step-by-step explanation:

The reaction of copper sulfate with zinc is shown below as:

`CuSO_4+Zn\rightarrow ZnSO_4+Cu`

Given that :

Amount of zinc = 2.9 g

Molar mass of zinc = 65.38 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus, molesare:

`moles= (2.9\ g)/(65.38\ g/mol)`

`moles= 0.0444\ mol`

From the reaction,

1 mole of zinc on reaction forms 1 mole of copper

Thus,

0.0444 moles of zinc on reaction forms 0.0444 mole of copper

Mass of copper = moles×Molar mass

Molar mass of copper = 63.54 g/mol

Mass of copper = 0.0444 ×63.54 g = 2.8212 g