Question

What are the roots of the quadratic equation? 6x2+5x−4=0 12 and −113 −12 and −113 −12 and 113 12 and 113

Answer 1

The roots of the quadratic equation are:

`x=(1)/(2)\ and\ x=(-4)/(3)`

Explanation:

Any quadratic equation of the type:

`ax^2+bx+c=0`

has solutions as:

`x=(-b\pm √(b^2-4ac))/(2a)`

Here we have quadratic equation as:

`6x^2+5x-4=0`

i.e.

`a=6\ ,\  b=5\ and\ c=-4`

Hence, the solution is given by:

`x=(-5\pm √(5^2-4* 6* (-4)))/(2* 6)\\\\i.e.\\\\x=(-5\pm √(25+96))/(12)\\\\i.e.\\\\x=(-5\pm √(121))/(12)\\\\i.e.\\\\x=(-5\pm 11)/(12)\\\\x=(-5+11)/(12)\ and\ x=(-5-11)/(12)\\\\x=(6)/(12)\ and\ x=(-16)/(12)\\\\x=(1)/(2)\ and\ x=(-4)/(3)`