Answer:
Intensity of first wave will 1/3 the intensity of second wave.
Step-by-step explanation:
Intensity of the wave is defined as the change in power with the respect to area of the wave.
Mathematically,

According to question, the power of the two waves are same but the area covers by the first wave is equal to 3 times the area cover by the second wave.
Therefore,

Now according to question,

Therefore, the intensity of first wave will become 1/3 times the intensity of second wave.