Question

What is Keq for an electrochemical reaction involving the transfer of 3 electrons, if E°cell = 0.652 V at

Answer 1

2.49 V.

Step-by-step explanation:

The formula which relates the equilibrium condition in the electrochemical cell is,

`logk_(eq)=(n)/(0.059)  E_(cell) ^(0)`

Given that the number of electron is 3 and the value of
`E^(0) _(cell)` is 0.652 V.

Now put these values in above equation.

`logk_(eq)=(3)/(0.059)  (0.652 V)\\logk_(eq)=33.15 V\\k_(eq)=e^(33.15)V\\k_(eq)=2.49V`

Therefore, the value of Keq for an electrochemical reaction is 2.49 V.