Answer:
Step-by-step explanation:
Energy falling on 1 m² surface of earth per second = 1050
Energy in one million years on 1 m²
= 1050 x 60 x 60 x 24 x 365 x 10⁶ = 3.311 x 10¹⁶ J
In order to calculate total energy coming out of the surface of the sun , we shall have to sum up this energy for the while spherical surface of imaginary sphere having radius equal to distance between sun and earth.
Area of this surface = 4π R² = 4 X 3.14 X (149.6 X 10⁹ )²
= 2.8 X 10²³ m²
So total energy coming out of the sun = 2.8 x 10²³ x 3.311 x 10¹⁶
= 9.271 x 10³⁹ J
From the formula
E = mc² { energy mass equivalence formula }
m = E / c² =

1.03 x 10²³ kg
mass of earth = 5.972 x 10²⁴
Answer in percentage of mass of earth
=

= 1.72 %