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The weights, in pounds, of the cats in an animal adoption center are normally distributed. If a random sample of cats is taken and the confidence interval is (7.9,12.7), what is the margin of error

User Journeyman
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1 Answer

2 votes

Answer: 2.4

Explanation:

Given : The weights, in pounds, of the cats in an animal adoption center are normally distributed.

The confidence interval is (7.9,12.7) (1)

Let
\overline{x} be the sample mean of the weights, in pounds, of the cats in an animal adoption center.

We know that the confidence interval for population mean is given by :-


(\overline{x}-E,\overline{x}+E) (2)

From (1) and (2)


\overline{x}-E=7.9-------(3)\\\\\overline{x}+E=12.7--------------(4)

Subtracting (3) from (4), we get


2E=4.8\\\\\Rightarrow\ E=2.4

Hence, the margin of error is E = 2.4

User Chethandb
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