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What is the range of the function f(x)=3x+2 if the domain is {-2,-1,0,2,5}

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Answer:

The range = {-4, -1, 2, 8, 17}

Explanation:

Put all values of x from the domain {-2, -1, 0, 2, 5} to f(x) = 3x + 2:

x = -2

f(-2) = 3(-2) + 2 = -6 + 2 = -4

x = -1

f(-1) = 3(-1) + 2 = -3 + 2 = -1

x = 0

f(0) = 3(0) + 2 = 0 + 2 = 2

x = 2

f(2) = 3(2) + 2 = 6 + 2 = 8

x = 5

f(5) = 3(5) + 2 = 15 + 2 = 17

User Afrig Aminuddin
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