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Given triangle ABC, cos A = sqrt2 /3 find the exact value of side a

1
2
sqrt2
sqrt7

Given triangle ABC, cos A = sqrt2 /3 find the exact value of side a 1 2 sqrt2 sqrt-example-1
User Zorayr
by
6.9k points

2 Answers

1 vote

Answer:

sqrt7

Explanation:

cosA = b/3 = sqrt2 /3

so b = sqrt2

apply the pythagorean theorem

a = sqrt7

User Justin Vartanian
by
6.7k points
0 votes

Answer: √7

Explanation:

cos A = adj / hyp = √2 / 3

We need to find the angle A before we proceed

cos A = 0.4714

A = arccos(0.4714)

A =61.87

adj =√2 hyp = 3 opp =a

sin A = opp / hyp

sin61.87 = a / 3

cross multiply

a = 3 sin 61.87

a = 3 × 0.88188

a =2.6456

a = √7

User Mecon
by
6.3k points
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