92.0k views
4 votes
(1 pt) Find a vector parametrization of the circle of radius 8 in the xy-plane, centered at (−3,−5), oriented counterclockwise. The point (5,−5) should correspond to t=0. Use t as the parameter in your answer.

1 Answer

1 vote

Answer:


x(t)=8 \cos(t) -3\\\\y(t)=8 \sin(t)-5

Explanation:

The equation of the circle centered at (-3,-5) in the xy-plane is


(x+3)^2+(y+5)^2=8^2

hence in vector parametrization, we have


x+3=8\cos(t)\\\\y+5=8\sin(t)

and so


x(t)=8\cos(t)-3\\\\y(t)=8\sin(t)-5

Moreover, note that


x(0)=8\cos(0)-3=8-3=5\\\\y(0)=8\sin(0)-5=0-5=-5

Otherwise, we should have used a parametrization and we are done.

User Mohammad Najar
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories