Question

A student collects 450. mL of HCl gas at a pressure of 101 kPa and a temperature of 17ºC. What would the volume of the gas be if the temperature was increased to 25ºC and the pressure was increased to 104 kPa?

Answer 1

449 mL

Step-by-step explanation:

Using Ideal gas equation for same mole of gas as

`\frac {{P_1}* {V_1}}{T_1}=\frac {{P_2}* {V_2}}{T_2}`

Given ,

V₁ = 450 mL

V₂ = ?

P₁ = 101 kPa

P₂ = 104 kPa

T₁ = 17 ºC

T₂ = 25 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (17 + 273.15) K = 290.15 K

T₂ = (25 + 273.15) K = 298.15 K

Using above equation as:

`\frac {{P_1}* {V_1}}{T_1}=\frac {{P_2}* {V_2}}{T_2}`

`\frac {{101}* {450}}{290.15}=\frac {{104}* {V_2}}{298.15}`

Solving for V₂ , we get:

V₂ = 449 mL