Question

The first ionization energy of a nitrogen atom is 2.32 aJ (attojoules). What is the frequency and wavelength, in nanometers, of photons capable of just ionizing nitrogen atoms?

Answer 1

Step-by-step explanation:

It is given that,

The ionization energy of a nitrogen atom,
`E=2.32\ aJ`

aJ is attpjoules.
`1\ aJ=10^(-18)\ J`

`E=2.32* 10^(-18)\ J`

The energy of an atom is given by :

`E=h* f`

f is the frequency of the photons

`f=(E)/(h)`

`f=(2.32* 10^(-18))/(6.67* 10^(-34))`

`f=3.47* 10^(15)\ Hz`

Also,
`E=(hc)/(\lambda)`

`\lambda=(hc)/(E)`

`\lambda=(6.67* 10^(-34)* 3* 10^8)/(2.32* 10^(-18))`

`\lambda=8.62* 10^(-8)\ m`

Hence, this is the required solution.