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Solve. Round to the nearest tenth.
6
2-12
19
2x-2
HELP ASAP!!

Solve. Round to the nearest tenth. 6 2-12 19 2x-2 HELP ASAP!!-example-1
User Mino
by
3.0k points

2 Answers

7 votes

Answer:


(6)/(19) = (x - 12)/(2x - 2) \\ 6(2x - 2) = 19(x - 12) \\ 12x - 12 = 19x - 228 \\ 7x = 216 \\ \boxed{x = 30.857}

30.857 is the right answer.

User Scott Muc
by
3.8k points
6 votes

Answer:


\displaystyle x = (216)/(7)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Explanation:

Step 1: Define


\displaystyle (6)/(19) = (x - 12)/(2x - 2)

Step 2: Solve for x

  1. Cross-multiply:
    \displaystyle 6(2x - 2) = 19(x - 12)
  2. Distribute:
    \displaystyle 12x - 12 = 19x - 228
  3. Isolate x terms:
    \displaystyle -12 = 7x - 228
  4. Isolate x term:
    \displaystyle 216 = 7x
  5. Isolate x:
    \displaystyle (216)/(7) = x
  6. Rewrite:
    \displaystyle x = (216)/(7)
User Arilwan
by
3.7k points