185k views
4 votes
How many moles of chloride ions are in 0.2550 g of aluminum chloride using AlCl3 's molar mass of 133.34 g / mol:?

2 Answers

1 vote
I got 0.001912 using dimensional analysis. See the picture for work.
How many moles of chloride ions are in 0.2550 g of aluminum chloride using AlCl3 's-example-1
User UTKARSH Sharma
by
6.5k points
0 votes

Step-by-step explanation:

It is known that number of moles is the amount of mass present in a given molar mass of the substance.

Mathematically, No. of moles =
\frac{mass}{\text{molar mass}}

We are given that mass of
AlCl_(3) is 0.255 g and molar mass of
AlCl_(3) is 133.34 g/mol.

Therefore, number of moles of
AlCl_(3) is calculated as follows.

No. of moles =
\frac{mass}{\text{molar mass}}

=
(0.255 g)/(133.34 g/mol)

=
1.912 * 10^(-3) mol

Since, there are three chlorine atoms present in one mole of
AlCl_(3). Therefore, moles of chlorine ions present in given 0.255 g will be calculated as follows.


3 * 1.912 * 10^(-3) mol

=
5.736 * 10^(-3) mol

Thus, we can conclude that
5.736 * 10^(-3) mol chloride ions are in 0.2550 g of aluminum chloride using
AlCl_(3)'s molar mass of 133.34 g/mol.

User Silkfire
by
6.4k points