Answer:
$3610.
Explanation:
We have been given that the traverses are adding a new room to their house. The room will be a cube with a volume of 6,859 cubic feet. We are supposed to find the hardwood floor's cost.
First of all, we will find side length of cube taking cube root of 6,869.
![\text{Side length of cube}=\sqrt[3]{6,859\text{ ft}^3}](https://img.qammunity.org/2020/formulas/mathematics/high-school/17uxdu6z5bwvzjzg9jqul3jjl8hdkg7ofa.png)
![\text{Side length of cube}=19\text{ ft}](https://img.qammunity.org/2020/formulas/mathematics/high-school/zhofilhsw8nw9e1un48g17cxw7pifv0kj5.png)
Now, we will find area of hardwood floor by taking square of 19 ft.
![\text{Area of hardwood floor}=(19\text{ ft})^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/eb4ag35z5roo1z0tp11h8dx3qygdww4y5h.png)
![\text{Area of hardwood floor}=361\text{ ft}^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/1olv094jv6wr2hrzhunutb6adknlla54jj.png)
Since hardwood floors costs $10 per square foot, so cost of square foot would be 10 times .
![\text{Total cost of hardwood floor}= \frac{\$10}{\text{ft}^2}* 361\text{ ft}^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/trpvgfx94fsupyaskpmxotsgod6uahqmjc.png)
![\text{Total cost of hardwood floor}=\$10*361](https://img.qammunity.org/2020/formulas/mathematics/high-school/ll59hxzsk2ilgv995t4htj2h9p70tte3w1.png)
![\text{Total cost of hardwood floor}=\$3610](https://img.qammunity.org/2020/formulas/mathematics/high-school/bjpuuyoistuscpxpdw6xqkj7x632kgbf0l.png)
Therefore, the cost of hardwood floor would be $3610.