Answer:
![X = 45√(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4o35osfbbo4dx5c07p1ccjar5p47jp8bdr.png)
Explanation:
All sides are of equal length.
![L = 45](https://img.qammunity.org/2020/formulas/mathematics/high-school/z5mqcsako783r6m4lg8gyzade6gxv098s2.png)
So the figure is a square.
To find the x side, which is the hypotenuse of the triangle, we use Pythagoras' theorem:
![X = √(L ^ 2 + S ^ 2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/1s62x1qglwueutyydn97k5sfyf64uybw2q.png)
Where
S is the length of the adjacent side and L is the length of the opposite side and X is the hypotenuse.
Since S and L are sides of a square, it is true that:
![S = L = 45](https://img.qammunity.org/2020/formulas/mathematics/high-school/hjbzwtwq3ycottmivo8gg09pgaj4m6m3rw.png)
So:
![X = √(L ^ 2 + L ^ 2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/byep0yaerezfp6it3c5tzli1tnsls39sew.png)
![X = √(2L ^ 2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/1hd0nv2tcjcjj9u986d3g1hozghr35tb6e.png)
![X = √(2)L](https://img.qammunity.org/2020/formulas/mathematics/high-school/bio08rtc8b0js8j9ygnpf0fckz5wh8qloz.png)
![X = 45√(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4o35osfbbo4dx5c07p1ccjar5p47jp8bdr.png)