Question

A fixed amount of an ideal monatomic gas is maintained at constant volume as it is cooled by 50 K. This feat is accomplished by removing 400 J of energy from the gas. How much work is done by the gas during this process

Answer 1

Answer: 0 Joules

Step-by-step explanation:

According to first law of thermodynamics:

`\Delta E=q+w`

`\Delta E`=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=
`-P\Delta V` {Work is done by the system when the final volume is greater than initial volume and is negative and vice versa}

Given : The volume is constant , i.e.
`\Delta V=0`

w = =[tex]-P\times 0=0J/tex]

Thus no work is done by the gas during this process.