Question

Help!!! please! im on my last try!

Solve using the zero product property:

(x + 3)(x - 5) = 0


x = 3 or x = -5

x = -3 or x = 5

x = 3 or x = 5

x = -3 or x = -5


Solve by factoring and applying the zero product property:

LaTeX: x^2-11x\:+28=0 x 2 − 11 x + 28 = 0


x = - 4 or x = - 7

x = - 4 or x = 7

x = 2 or x = 14

x = 4 or x = 7


For what values of x is the equation true? (Form 1st!)

LaTeX: \:x^2-5x=36 x 2 − 5 x = 36


4 and -9

- 4 and - 9

- 4 and 9

4 and 9


For what values is the following true? (Form 1st!)

LaTeX: x^2+2x-4=20 x 2 + 2 x − 4 = 20


x = 4 or x = - 6

x = - 4 or x = 6

x = 2 or x = 4

x = - 2 or x = - 4


To find the solution to the equation using factoring, we need to first write it in standard form. Which of the following choices is equivalent to the equation:

(x −2)(x + 5) = 18


LaTeX: x^2+3x-28=0 x 2 + 3 x − 28 = 0

LaTeX: x^2-3x-28=0 x 2 − 3 x − 28 = 0

LaTeX: x^2+3x+8=0 x 2 + 3 x + 8 = 0
x^2+3x+28=0

Answer 1

1. x = -3 or x = 5

2. x = 4 or x = 7

3. - 4 and 9

4. x = 4 or x = - 6

5. Unfortunately I got this one wrong, but put the answers above and you'll get an 80%

Answer 2

1) Option 2 - x=-3 or x=5

2) option 4 - x=4 or x=7

3) Option 3 - x=-4 or x=9

4) Option 1 - x=4 or x=-6

5) Option 1 -
`x^2+3x-28=0`

Explanation:

1) Solve using the zero product property
`(x + 3)(x - 5) = 0`

Solution :

Zero product property states that if ab=0 then a=0 or b=0.

Applying,
`(x + 3)(x - 5) = 0`

Either
`x+3=0` or
`x-5=0`

Either
`x=-3` or
`x=5`

So, Option 2 is correct.

2) Solve by factoring and applying the zero product property
`x^2-11x+28=0`

Solution :

`x^2-11x+28=0`

Applying middle term split,

`x^2-4x-7x+28=0`

`x(x-4)-7(x-4)=0`

`(x-4)(x-7)=0`

Applying zero product property,

Either
`x-4=0` or
`x-7=0`

Either
`x=4` or
`x=7`

So, Option 4 is correct.

3) Solve by factoring and applying the zero product property
`x^2-5x=36`

Solution :

`x^2-5x-36=0`

Applying middle term split,

`x^2-9x+4x-36=0`

`x(x-9)+4(x-9)=0`

`(x-9)(x+4)=0`

Applying zero product property,

Either
`x-9=0` or
`x+4=0`

Either
`x=9` or
`x=-4`

So, Option 3 is correct.

4) For what values is the following true?
`x^2+2x-4=20`

Solution : To get the result we factor the equation,

`x^2+2x-24=0`

Applying middle term split,

`x^2+6x-4x-24=0`

`x(x+6)-4(x+6)=0`

`(x+6)(x-4)=0`

Applying zero product property,

Either
`x+6=0` or
`x-4=0`

Either
`x=-6` or
`x=4`

So, Option 1 is correct.

5) To find the solution to the equation using factoring, we need to first write it in standard form. Which of the following choices is equivalent to the equation :
`(x-2)(x + 5) = 18`

Solution :

To write in standard form we just multiply the terms,

`(x-2)(x + 5)=18`

`x^2+5x-2x-10=18`

`x^2+3x-10=18`

`x^2+3x-10-18=0`

`x^2+3x-28=0`

So, Option 1 is correct.