100k views
0 votes
Suppose the number of free throws in a basketball game by one player are normally distributed with a standard deviation 0.97 free throws. A random sample of basketball players from the population produces a sample mean of x¯=4.9 free throws. What value of z should be used to calculate a confidence interval with a 95% confidence level? 20.10 1.282 20.05 1.645 0.025 1.960 20.005 2.576 2.326

User Iannazzi
by
8.6k points

1 Answer

2 votes

Answer: 1.960

Explanation:

The value of z we use to calculate a confidence interval with a (
1-\alpha) confidence level is a two-tailed test value i.e. represented by :-


z_(\alpha/2)

Given : The level of confidence:
1-\alpha=0.95

Then, significance level :
\alpha: 1-0.95=0.05

With the help of standard normal distribution table for z , we have


z_(\alpha/2)=z_(0.05/2)=z_(0.025)=1.960

Hence, the value of z should be used to calculate a confidence interval with a 95% confidence level =1.960

User Hastur
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories