Question

Lindsay​ Electronics, a small manufacturer of electronic research​ equipment, has approximately 6 comma 800 items in its inventory and has hired Joan​ Blasco-Paul to manage its inventory. Joan has determined that 8​% of the items in inventory are A​ items, 33​% are B​ items, and 59​% are C items. She would like to set up a system in which all A items are counted monthly​ (every 19 working​ days), all B items are counted quarterly​ (every 60 working​ days), and all C items are counted semiannually​ (every 118 working​ days). How many items need to be counted each​ day? The total number of items that need to be counted each day is nothing items ​(round your response to the nearest whole​ number).

Answer 1

100 items need to be counted each day.

Step-by-step explanation:

Of the 6,800 items, 544 are A items (0.08 * 6,800), 2,244 are B items (0.33 * 6,800) and 4,012 are C items (0.59 * 6,800). If you want to count every day the same number of items, you have to divide the number of items A, B and C for the days between being counted twice. So, if you have to count each day a number of items A, the amount is 544/19 working days, that is 28.6315789. The same with B (2,244/60 = 37.4) and with C (4,012/118 = 34). Each day, you have to count 28.63 A plus 37.4 B plus 34 C. 28.63+37.4+34=100.03.