Answer:
Option D. A number line with an open circle on 4 with shading to the right and a closed circle on 10 with shading to the left
Explanation:
we have

Divide the compound inequality into two inequalities
-----> inequality A
Multiply by -1 both sides

Divide by 5 both sides

The solution of inequality A is the interval ----> (-∞,10]
All real numbers less than or equal to 10
-----> inequality B


Multiply by -1 both sides

Divide by 5 both sides

Rewrite

The solution of the inequality B is the interval ----> (4,∞)
All real numbers greater than 4
The solution of the compound inequality is
(-∞,10] ∩ (4,∞)= (4,10]
All real numbers greater than 4 and less than or equal to 10
A number line with an open circle on 4 with shading to the right and a closed circle on 10 with shading to the left