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How many words of five letters can be created that start with the letter T, contain 2 other consonats and end with 2 vowels? Note that a word is any combination of 5 letters but letters cannot be repeated.

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If we're only counting 5 vowels (A, E, I, O, U) and 20 consonants (everything else, minus T), then there are


\dbinom52=(5!)/(2!(5-2)!)=10

ways of picking the vowels, and


\dbinom{20}2=(20!)/(2!(20-2)!)=190

ways of picking the consonants.

We want the word to start with T, and we'll allow any arrangement of the other 4 letters, so that the total number of words is


4!\dbinom52\dbinom{20}2=\boxed{45,600}

Keep in mind that this means words like TRIES and TIRES are treated as different.

User Sathish Naga
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