Question

3. The electric field of a sinusoidal electromagnetic wave has an amplitude of 5.0 V/m. How much radiation energy passes through a 1.5 m2 window perpendicular to the wave during one hour? a) 258 J b) 459 J c) 351 J d) 531 J e) 179 J

Answer 1

e)
`179` J

Step-by-step explanation:

`E_(o)` = Magnitude of electric field = 5 V/m

`A` = Area of window = 1.5 m²

`c` = speed of electromagnetic wave = 3 x 10⁸ m/s

`\Delta t` = time interval = 1 h = 3600 sec

radiation energy is given as

`U = (0.5)\epsilon _(o)E_(o)^(2)cA\Delta t`

`U = (0.5)(8.85* 10^(-12))(5)^(2)(3* 10^(8))(1.5)(3600)`

`U = 179` J