Question

A sample of argon has a volume of 205 mL when its temperature is -44.0 oC and its pressure is 712 mm of Hg. What would be the volume of the argon at STP?

Answer 1

The volume of the argon at STP is 228.95 mL.

Step-by-step explanation:

Given that,

Initial volume = 205 mL

Initial temperature = -44.0 °C = 229\ K

Final temperature = 273 K

Initial pressure = 712 mm Hg

Final pressure = 760 mm Hg

We need to calculate the volume of the argon at STP

Using gas law

`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`

Put the value into the formula

`(712*205)/(229)=(760* V_(2))/(273)`

`V_(2)=(712*205*273)/(229*760)`

`V_(2)=228.95\ mL`

Hence, The volume of the argon at STP is 228.95 mL.

Answer 2

231.98 mL

Step-by-step explanation:

V₁ = Initial volume = 205 mL

V₂ = Final volume

P₁ = Initial pressure = 712 mmHg

P₂ = Final pressure = 750 mmhg (STP)

T₁ = Initial temperature = -44 °C = 229.15 K

T₂ = Final temperature = 273.15 K (STP)

From Combined gas law

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)\\\Rightarrow V_2=(P_1V_1T_2)/(T_1P_2)\\\Rightarrow V_2=(712* 205* 273.15)/(229.15* 750)=231.98\ mL`

Volume of the argon at STP is 231.98 mL