Step-by-step explanation:
It is given that,
Initial speed of the automobile, u = 65 km/hr =
Final speed of the automobile, v = 0
Deceleration of the automobile,
![a=-6\ m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/gqadig8ovkjtsxf3aoe4qt902gn21qdbdq.png)
We need to find the distance covered by the car as it comes to rest. It can be calculated using third equation of motion as :
![v^2-u^2=2ax](https://img.qammunity.org/2020/formulas/physics/high-school/x5mc0vmr61ayp8l0vus6emuvrae4wdby6e.png)
![a=(v^2-u^2)/(2x)](https://img.qammunity.org/2020/formulas/physics/high-school/ao9emnkg0iy2u6ja4swgzm4vhpbqtxp5h4.png)
![a=27.15\ m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/22b5e3c90jrchfb0441cfjdcrz71brau7l.png)
So, the acceleration of the car is
. Hence, this is the required solution.