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You plan to invest in bonds that pay 6.0%, compounded annually. If you invest $10,000 today, how many years will it take for your investment to grow to $25,000?

User Philio
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1 Answer

4 votes

Answer:

The answer is 16 years.

Step-by-step explanation:

The formula for calculating the value of an investment that is compounded annually is given by:


V(n)=(1+R)^nP

Where:


n is the number of years the investment is compounded,


R is the annual interest rate,


P is the principal investment.

We know the following:


25000=(1+0.06)^n * 10000

And we want to clear the value n from the equation.

The problem can be resolved as follows.

First step: divide each member of the equation by
10,000:


( 25000)/(10000)=(1+0.06)^n * ( 10000)/(10000)


2.5=(1.06)^n

Second step: apply logarithms to both members of the equation:


log(2.5)=log (1.06)^n

Third step: apply the logarithmic property
logA^n=n.logA in the second member of the equation:


log(2.5)=n.log (1.06)

Fourth step: divide both members of the equation by
log1.06


(log(2.50))/(log (1.06)) =n


n= 15.7252

We can round up the number and conclude that it will take 16 years for $10,000 invested today in bonds that pay 6% interest compounded annually, to grow to $25,000.

User Orbiting Eden
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