Answer:
The answer is 16 years.
Step-by-step explanation:
The formula for calculating the value of an investment that is compounded annually is given by:
![V(n)=(1+R)^nP](https://img.qammunity.org/2020/formulas/business/college/4b4fg1jaemqlimws32dsznlwk6juetkqhj.png)
Where:
is the number of years the investment is compounded,
is the annual interest rate,
is the principal investment.
We know the following:
![25000=(1+0.06)^n * 10000](https://img.qammunity.org/2020/formulas/business/college/6aq94n11sin39ge75l7bjki1mr7rbx5qix.png)
And we want to clear the value n from the equation.
The problem can be resolved as follows.
First step: divide each member of the equation by
:
![( 25000)/(10000)=(1+0.06)^n * ( 10000)/(10000)](https://img.qammunity.org/2020/formulas/business/college/oq7ndpd7tp39wsfbh47b4tdcpq6tlgfoqs.png)
![2.5=(1.06)^n](https://img.qammunity.org/2020/formulas/business/college/ks50vcwbe6cw4bxjpx4v3ngjo6oqyzwn88.png)
Second step: apply logarithms to both members of the equation:
![log(2.5)=log (1.06)^n](https://img.qammunity.org/2020/formulas/business/college/t3cync9umvdmjm7nygl5m3v9b3raefirm2.png)
Third step: apply the logarithmic property
in the second member of the equation:
![log(2.5)=n.log (1.06)](https://img.qammunity.org/2020/formulas/business/college/smx9h27uw6gt45dsgo7a7klvhf7uc0t9i0.png)
Fourth step: divide both members of the equation by
![log1.06](https://img.qammunity.org/2020/formulas/business/college/ejyd18rxkie72xqr3we9xg24k4vb90k1hw.png)
![(log(2.50))/(log (1.06)) =n](https://img.qammunity.org/2020/formulas/business/college/1s7v2x8uonh9rl6j2z6frko2q8zf8frd2j.png)
![n= 15.7252](https://img.qammunity.org/2020/formulas/business/college/wo4hjyng03f2kakbing7zmetcrg7glyt2u.png)
We can round up the number and conclude that it will take 16 years for $10,000 invested today in bonds that pay 6% interest compounded annually, to grow to $25,000.