Answer:
![102.9in^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/e4deolwg7zx8qc6a64qeopiq3275yzrg23.png)
Explanation:
In order to calculate the space between the sphere and the cube we need to calculate the volume of the cube and then the volume of the sphere. I have attached an illustration below to help you better understand the situation.
![Volume.Cube = a^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/oq2x4jxm4hmjcy5g1wqd4x3vf4xu483l5o.png)
.... r is radius which is half of diameter.
Now that we know the formulas we can solve for the volumes.
![Volume.Cube = 6^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/an056hizt6he3ypkss7s3ggs8benqtdbil.png)
![Volume.Cube = 216.in^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8ick0yh0j57xmt6f3cl5yawu0rireviee5.png)
![Volume.Sphere = (4)/(3)*\pi *r^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/iagp2hhw2u7ni12zf6kwas0vpwrgnicd82.png)
![Volume.Sphere = 113.097in^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/p8n4zjlpd3dyk9phlfuv0orm9pyryxak2f.png)
Now we can subtract the volume of the sphere from the volume of the cube in order to calculate the space between them
![216-113.1 = 102.9in^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/mvf2uv21la0q1cjq4zbtg0j4ruua2zxcjc.png)
The space between is that of
![102.9in^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/e4deolwg7zx8qc6a64qeopiq3275yzrg23.png)