Question

A 6.5-g iron meteor hits the earth at a speed of 295 m/s. If its kinetic energy is entirely converted to heat in the meteor, by how much will its temperature rise?

Answer 1

The temperature rise is 92°.

Step-by-step explanation:

Given that,

Mass of iron = 6.5 g

Speed = 295 m/s

We know that,

specific heat of iron = 113 cal/Kg C°

1 cal = 4.186 J/kg C°

We need to calculate the temperature

Using formula of kinetic energy

`K.E=(1)/(2)mv^2`...(I)

Formula of heat

`Q=mc\Delta T`....(II)

From equation (I) and (II)

`(1)/(2)mv^2=mc\Delta T`

`\Delta T=(1)/(2)*(v^2)/(c)`

Put the value into the relation

`\Delta T=(295^2)/(2*473.018)`

`\Delta T=91.9=92^(\circ) C`

Hence, The temperature rise is 92°.