Answer:
Explanation:
Let x be the wait times before a call is answered in phone calls.
The claim is x bar <3.3 minutes
Sample size n =62
Sample mean - x bar = 3.24 minutes
Population std dev =
![\sigma = 0.40 minutes\\](https://img.qammunity.org/2020/formulas/mathematics/college/ysi7eqedrsomgxgb8jsdirq5rssvv0uvtw.png)
Since population std dev is known and also sample size is sufficiently large, we can use Z test.
![H_0: x bar = 3.3\\H_a: x bar <3.3](https://img.qammunity.org/2020/formulas/mathematics/college/r8sp1e5p18d685qetnzr65zi0rlh7a62id.png)
(one tailed test)
Mean difference = 3.24-3.3 = -0.06 min
Std error of sample =
![(\sigma)/(√(n) ) =(0.40)/(√(62) ) \\=0.0508](https://img.qammunity.org/2020/formulas/mathematics/college/scvc3c9hvhf9amnpcfy8fvixt9mbydpr11.png)
Z = tset statistic =
![(-006)/(0.0508) \\\\=-1.18](https://img.qammunity.org/2020/formulas/mathematics/college/dr5uuc93sdd5p34mh5xf0fk1fpr1qsdn78.png)
p value = 0.119
Since p value > alpha, we accept null hypothesis.
There is no evidence to support the claim at alpha = 0.08